Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.6 - Transformations of Functions - 2.6 Exercises - Page 206: 24

Answer

See the image below. (a) Blue graph. (b) Red graph. (c) Green graph (d) Purple graph

Work Step by Step

To graph the following functions we will use the parent function $y=\sqrt{x}$ and apply transformations. (Note, the black dotted line in the image is parent function $y=\sqrt{x}$) (a) $g(x)=\sqrt{x-2}$, This means that we have to shift the parent function to the right-hand side by $2$ units. And we will get the $Blue$ graph, shown in the image above. (b) $g(x)=\sqrt{x}+1$, This means that we have to shift the parent function upwards by $1$ unit. So, we will get the $Red$ graph, shown in the image above (c) $g(x)=\sqrt{x+2}+2$. In this case we have to apply $2$ transformations. (Note, it doesn't matter which one we apply first). Let's apply the transformation in square root first, which means that we have to move the parent function to the left-hand side by $2$ units. Then apply the $+2$, which means to shift the previous function upwards by $2$ units. At last we will have the $Green$ graph, shown in the image above. (d) $g(x)=-\sqrt{x}+1$. The same idea is here (as we did in (c)) we have to apply 2 transformations. Let's first apply the $minus$ sign at the beginning. It simply means to reflect the parent function about $x$-axis. Then apply the $+1$, which means to shift the previous function upwards by 1 unit. At last we will get the $Purple$ graph, shown in the image above.
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