Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.5 - Linear Functions and Models - 2.5 Exercises - Page 197: 49

Answer

(a) $C(x) = \frac 14 x + 260$ (b) Image below (c) $0.25/mi ------

Work Step by Step

(a) If $C(x)$ represents the driving cost and $x$ represents the number of miles driven: $$C(x) = ax + b$$ $$a = \frac{460 - 380}{800 - 480} = \frac{80}{320} = \frac 1 4$$ Now, substitute some of the values into the equation to find the $b$ value. $$C(x) = ax + b \longrightarrow 380 = (\frac 1 4)(480) + b$$ $$380 = 120 + b$$ $$b = 380 - 120 = 260$$ $$C(x) = \frac 14 x + 260$$ (b) Plot the following points: $(480,380)$ and $(800,460)$. Then draw the line that passes through both points. (c) Rate of change (cost increase) = a = $\frac 14 = 0.25$ Since $C(x)$ is in $\$$ and $x$ in miles: $\$0.25/mi $
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