Answer
$a.\quad x=-2,\ x=1$
$b.\quad -2 \leq x \leq 1$
Work Step by Step
$a.$
Graph $y=x^{2}$ (red on the image)
and $y=2-x$ (blue).
The solution (if it exists) is the x-coordinate of the intersection.
Solution: $x=-2,\ x=1$
$b.$
Using the graphs of part (a), we see that
the red graph is below or intersecting the blue graph when $-2 \leq x \leq 1$