Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.1 - Sequences and Summation Notation - 12.1 Exercises: 62

Answer

sum = $0+\sqrt{\frac{1}{3}}+\sqrt{\frac{1}{2}}+\sqrt{\frac{3}{5}}$

Work Step by Step

$a_{j}=\sqrt{\frac{j-1}{j+1}}$ $j=1,\qquad a_{1}=\sqrt{\frac{1-1}{1+1}}=0$ $j=2,\qquad a_{2}=\sqrt{\frac{2-1}{2+1}}=\sqrt{\frac{1}{3}}$ $j=3, \qquad a_{3}=\sqrt{\frac{3-1}{3+1}}=\sqrt{\frac{2}{4}}=\sqrt{\frac{1}{2}}$ $j=4, \qquad a_{3}=\sqrt{\frac{4-1}{4+1}}=\sqrt{\frac{3}{5}}$ sum = $0+\sqrt{\frac{1}{3}}+\sqrt{\frac{1}{2}}+\sqrt{\frac{3}{5}}$
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