Answer
1st term: $\frac{1}{3}$ 2nd term: $\frac{1}{5}$ 3rd term: $\frac{1}{7}$ 4th term: $\frac{1}{9}$ 100th term: $\frac{1}{201}$
Work Step by Step
To find the nth term of sequence, plug in a number for n. So, for the first term, plug in 1 for n, for the second term, plug in 2 for n, and so on. In this case:
1. 1st term: $\frac{1}{2n+1}$ = $\frac{1}{2(1) + 1}$ = $\frac{1}{3}$
2. Repeat this for the next 3 terms, plugging in 2 for n, 3 for n, and then 4 for n, and solving.
3. For the 100th term: $\frac{1}{2n+1}$ = $\frac{1}{2(100) + 1}$ = $\frac{1}{201}$
