Answer
(a) Focus: $F(4,0)$
Directrix: $x=-4$
$Focal~diameter=16$
(b)
Work Step by Step
Equation of a parabola with horizontal axis: $y^2=4px$
$y^2=16x$
$4p=16$
$p=4$
Focus: $F(p,0)=F(4,0)$
Directrix: $x=-p=-4$
$Focal~diameter=|4p|=16$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 11 - Section 11.1 - Parabolas - 11.1 Exercises - Page 788: 14
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