Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 11 - Review - Test - Page 835: 14

Answer

$(x-2)^2=8(y-2)$

Work Step by Step

Step 1. Identify the given quantities: parabola focus $(2,4)$, directrix the x-axis or $y=0$ Step 2. The directrix is horizontal, we can assume the equation as $(x-h)^2=4p(y-k)$ Step 3. The vertex is in the middle between the focus and the directrix $V(2,2)$ which gives $h=2, k=2$ Step 4. The value $p$ is the distance between the vertex and the focus, we have $p=4-2=2$ Step 5. The equation for the parabola can be written as $(x-2)^2=8(y-2)$
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