Answer
$M_{32}=\dfrac{7}{2}$
and
$A_{32}=-\dfrac{7}{2}$
Work Step by Step
The minor of an element is defined $a_{ij}$of a determinant is defined as the determinant obtained by deleting its ith row and jth columns and the minor $M$ of an element $a_{ij}$ is abbreviated as $M_{ij}$.
Further, the cofactor of an element $a_{ij}$ is abbreviated as $A_{ij}$.
where $A_{ij}=(-1)^{i+j} M$
Here, $M_{32}=\begin{vmatrix}1&\dfrac{1}{2}\\-3&2\end{vmatrix}=(1)(2)-(-3)(\dfrac{1}{2})=\dfrac{7}{2}$
and
$A_{32}=(-1)^{3+2} M_{32}=(-1)(\dfrac{7}{2})=-\dfrac{7}{2}$
