Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.3 - Matrices and Systems of Linear Equations - 10.3 Exercises - Page 711: 71

Answer

$5$ miles of Running, $2$ miles of Swimming, $30$ miles of Cycling.

Work Step by Step

Step 1. Establish the system of equations, assume $x$ miles of Running, $y$ miles of Swimming, and $z$ miles of Cycling : $\begin{cases} x/10+y/4+z/20=2.5 (hours) \\ x/7.5+y/6+z/15=3 (hours) \\ x/15+y/3+z/40=1.75 (hours) \end{cases}$ Step 2. Remove the fractions of the above equations: $\begin{cases} 2x+5y+z=50 \\ 4x+5y+2z=90 \\ 8x+40y+3z=210 \end{cases}$ Step 3. Establish the augmented matrix of the system and use the Gauss Eliminations method: $\begin{vmatrix} 2 & 5 & 1 & 50 \\4 & 5 & 2 & 90\\8 & 40 & 3 & 210 \end{vmatrix} \begin{array}( .\\2R_1-R_2\to R_2\\R_3-4R_1\to R_3\\ \end{array}$ Step 4. Do the operations given on the right side of the matrix. $\begin{vmatrix} 2 & 5 & 1 & 50 \\0 & 5 & 0 & 10\\0 & 20 & -1 & 10 \end{vmatrix} \begin{array}( .\\.\\.\\ \end{array}$ Step 5. Row 2 gives $5y=10$ and $y=2$mi. Row 3 gives $20y-z=10$ which leads to $z=30$mi. Row 1 gives $2x+5y+z=50$ thus $x=5$mi Step 6. The final results are: $5$ miles of Running, $2$ miles of Swimming, and $30$ miles of Cycling.
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