Answer
-3;
$4y-5z=-4$
Work Step by Step
$x-y+z=2$
$3x+y-2z=2$
Multiply the first equation by -3 and add it to the third one.
$-3x+3y-3z=-6$
$3x+y-2z-3x+3y-3z=2-6$
$4y-5z=-4$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 10 - Section 10.2 - Systems of Linear Equations in Several Variables - 10.2 Exercises - Page 696: 2
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