Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.1 - Real Numbers - 1.1 Exercises: 82



Work Step by Step

$a+b+|a-b|,$ where $a\lt b$ Since $a\lt b$, the substraction inside the absolute value bars will result in a negative number. To express this quantity without the absolute value bars, we must change its sign. After that, simplify the resulting expression: $a+b+|a-b|=a+b-(a-b)=a+b-a+b=2b$
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