Answer
$x_1=-1-i\frac{\sqrt{2}}{2}$
$x_2=-1+i\frac{\sqrt{2}}{2}$
Work Step by Step
$2x^2+4x+3=0$
We solve the equation as a quadratic equation:
$D=b^2-4ac=16-24=-8$
$x_1=\frac{-b-\sqrt{D}}{2a}=\frac{-4-\sqrt{-8}}{4}=\frac{-4-\sqrt{8}i}{4}=\frac{-4-2\sqrt{2}i}{4}=\frac{-2-\sqrt{2}i}{2}=-1-i\frac{\sqrt{2}}{2}$
$x_2=\frac{-b+\sqrt{D}}{2a}\frac{-4+\sqrt{-8}}{4}=\frac{-4+\sqrt{8}i}{4}=\frac{-4+2\sqrt{2}i}{4}=\frac{-2+\sqrt{2}i}{2}=-1+i\frac{\sqrt{2}}{2}$
