Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Fitting Lines to Data - Problems - Page 145: 5

Answer

$(a)$ See the image below. $(b)$ $y = 4.85667x - 220.96667$ $(c)$ $\approx 265$ $chirps/min$

Work Step by Step

$(a)$ See the image above. $(b)$ We can find the function using regression line calculator: $y = 4.85667x - 220.96667$ $y$ stands for the chirping rate for given $x$ temperature. $(c)$ If $x=100°F$ $y= 4.85667\times100 - 220.96667\approx 265$
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