Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises - Page 133: 4

Answer

Distributive Property

Work Step by Step

$State$ $the$ $property$ $of$ $real$ $numbers$ $being$ $used:$ $(A+1)(x+y) = (A+1)x + (A+1)y$ We distribute the x and y to $(A+1)$ twice for both terms hence (A+1)x and (A+1)y. This is proven true if we factor the (A+1) which equals (A+1)(x+y).
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