## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

a) The $x$-intercept is $-4$. The $y$-intercept is $3$. b) See the graph below.
a) In order to find the $x$-intercept, let $y=0$ and we have to solve the equation. $-0.3x+0.4y=1.2$ $-0.3x+0.4(0)=1.2$ $-0.3x=1.2$ $x=-4$ The $x$-intercept is $-4$ and the point $(-4,0)$ is on the line. In order to find the $y$-intercept, let $x=0$ and we have to solve the equation. $-0.3+0.4y=1.2$ $-0.3(0)+0.4y=1.2$ $0.4y=1.2$ $y=3$ The $y$-intercept is $3$ and the point $(0,3)$ is on the line. b) In order to sketch the line, we only have to plot the intercepts then connect them using a line.