Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 9 - Analytic Geometry - Section 9.6 Polar Equations of Conics - 9.6 Assess Your Understanding - Page 705: 49

Answer

$\pi,\frac{\pi}{3},\frac{5\pi}{3}$

Work Step by Step

1. Treat $cos(x)$ as a single unit, we have $(2cos(x)-1)(cos(x)+1)=0$, thus $cos(x)=-1, \frac{1}{2}$ 2. For $cos(x)=-1$, we have $x=\pi$ within $[0,2\pi)$, 3. For $cos(x)=\frac{1}{2}$, we have $x=\frac{\pi}{3},\frac{5\pi}{3}$ within $[0,2\pi)$,
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