Answer
$617.1\ lb\cdot ft$
Work Step by Step
The horizontal component of the force is $F=80cos50^\circ\ lb$, the moving distance is $d=12-0=12\ ft$, thus the work done is $W=F\cdot d=(12)80cos50^\circ\approx617.1\ lb\cdot ft$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 9 - Analytic Geometry - Section 9.3 The Ellipse - 9.3 Assess Your Understanding - Page 679: 91
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