Answer
$c$
Work Step by Step
The general equation for a parabola that has an axis of symmetry parallel to the $y$-axis and opens up is given by: $(x−h)^2=4a(y−k)$
Where, $(h, k)$ is the vertex of the parabola.
We are given that the coordinates for the vertex are $(3,2)$ and the focus is $f=4$ units with coordinates: $(3, 2+f) \to (3,6)$ and directrix $y=k-a =2-4=-2$
Therefore, the required option is $(c)$.