Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 9 - Analytic Geometry - Cumulative Review - Page 720: 5

Answer

(a) $18$, (b) $(2,18]$.

Work Step by Step

Given $f(x)=log_4(x-2)$, we have: (a) $f(x)=2\Longrightarrow log_4(x-2)=2\Longrightarrow x-2=4^2 $, thus $x=18$, check, it fits. (b) $f(x)\le2\Longrightarrow log_4(x-2)\le2\Longrightarrow x-2\le4^2 $, thus $x\le18$. together with domain $x\gt2$, we have the solution $(2,18]$.
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