Answer
$[-3,2]$
Work Step by Step
$6-x\ge x^2$,
$x^2+x-6\le0$,
$(x+3)(x-2)\le0$,
The $\le$ sign means that the solution should be within the region defined be the boundary points, thus we have the solution $[-3,2]$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 9 - Analytic Geometry - Cumulative Review - Page 720: 3
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