Answer
$-12$
Work Step by Step
The determinant for a $ 2 \times 2$ matrix can be found as:
$det = \begin{vmatrix}
A & B \\
C & D \\ \end{vmatrix}=AD-BC$
As per the problem,
$det=\begin{vmatrix}
-4 & 0 \\
5 & 3 \\ \end{vmatrix}=(-4)(3)-(0)(5)=-12-0=-12$
