Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.4 Vectors - 8.4 Assess Your Understanding - Page 630: 101



Work Step by Step

Note that $\sqrt[3]{x-2}=3 \Rightarrow(x-2)^{1 / 3}=3$ Raise both sides to the third power to eliminate the fractional exponent: $((x-2)^\frac{1}{3})^3=3^{3}$ $(x-2)^1=27$ $x-2=27$ $x=27+2$ $x=29$
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