## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$x=29$
Note that $\sqrt[3]{x-2}=3 \Rightarrow(x-2)^{1 / 3}=3$ Raise both sides to the third power to eliminate the fractional exponent: $((x-2)^\frac{1}{3})^3=3^{3}$ $(x-2)^1=27$ $x-2=27$ $x=27+2$ $x=29$