Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.3 The Complex Plane; De Moivre's Theorem - 8.3 Assess Your Understanding - Page 616: 72

Answer

$2y\sqrt[3] {3x^2y^2}$

Work Step by Step

Based on the given conditions, we have: $\sqrt[3] {24x^2y^5}=\sqrt[3] {3\cdot 2^3x^2y^2y^3}=2y\sqrt[3] {3x^2y^2}$
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