Answer
$ 2(cos60^\circ+i\ sin60^\circ)$, $ 2(cos180^\circ+i\ sin180^\circ)$, $ 2(cos300^\circ+i\ sin300^\circ)$.
Work Step by Step
Based on the given conditions, we have:
$-8=8(cos180^\circ+i\ sin180^\circ)$, $(-8)^{1/3}=2(cos(\frac{360k+180}{3})^\circ+i\ sin(\frac{360k+180}{3})^\circ)$, $k=0, z_0= 2(cos60^\circ+i\ sin60^\circ)$, $k=1, z_1= 2(cos180^\circ+i\ sin180^\circ)$, $k=2, z_2= 2(cos300^\circ+i\ sin300^\circ)$.
