Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.2 Polar Equations and Graphs - 8.2 Assess Your Understanding - Page 606: 24

Answer

$(x+2)^2+(y)^2=4$ a circle with center $(-2,0)$, radius $r=2$. See graph.

Work Step by Step

1. Use the formula $r^2=x^2+y^2, r\ cos\theta=x$, we have $r=-4cos\theta\rightarrow r^2=-4r\ cos\theta \rightarrow x^2+y^2=-4x \rightarrow (x+2)^2+(y)^2=4$ 2. We can identify the above equation as a circle with center $(-2,0)$, radius $r=2$. 3. See graph.
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