Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.1 Polar Cordinates - 8.1 Assess Your Understanding - Page 593: 90

Answer

$\left(-\dfrac{5}{4},\dfrac{9}{2}\right)$

Work Step by Step

The midpoint $M$ of the line segment joining the points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the formula $$M=\left(\dfrac{x_{1}+x_{2}}{2},\dfrac{y_{1}+y_{2}}{2}\right)$$ Substituting the coordinates of the given points into the formula above gives: $M=\left(\dfrac{x_{1}+x_{2}}{2},\dfrac{y_{1}+y_{2}}{2}\right)$ $M=\left(\dfrac{-3+\frac{1}{2}}{2},\dfrac{7+2}{2}\right)$ $M=\left(-\dfrac{5}{4},\dfrac{9}{2}\right)$
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