Answer
$-\frac{\pi}{6}$
Work Step by Step
Let $sin^{-1}(-\frac{1}{2})=t$ (in quadrant IV), we have $sin(t)=-\frac{1}{2}$, thus $t=-\frac{\pi}{6}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 8 - Polar Coordinates; Vectors - Cumulative Review - Page 657: 9
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