Answer
$-9i-5j+3k$
Work Step by Step
Given $\vec u=<2,-3,1>$ and $\vec v=<-1,3,2>$,
use the formula for cross product, we have
$\vec u\times\vec v=(-3*2-3*1)i+(1*(-1)-2*2)j+(2*3-(-1)*(-3))k=-9i-5j+3k$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 8 - Polar Coordinates; Vectors - Chapter Test - Page 657: 23
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