Answer
$f^{-1}(x)=\frac{4x-3}{x-1}, x\ne1$
Work Step by Step
$f(x)=\frac{x-3}{x-4}$,
$y=\frac{x-3}{x-4}$,
$x=\frac{y-3}{y-4}$,
$y=\frac{4x-3}{x-1}$,
$f^{-1}(x)=\frac{4x-3}{x-1}, x\ne1$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 7 - Applications of Trigonometric Functions - Section 7.5 Simple Harmonic Motion; Damped Motion; Combining Waves - 7.5 Assess Your Understanding - Page 577: 65
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