Answer
(a) $f(x) =\frac{1}{2}cos(\frac{x}{2})-\frac{1}{2}cos(\frac{3x}{2})$
(b) See graph (red).
Work Step by Step
(a) $f(x)=sin(2x)sin(x)=\frac{1}{2}cos(\frac{2x-x}{2})-\frac{1}{2}cos(\frac{2x+x}{2})=\frac{1}{2}cos(\frac{x}{2})-\frac{1}{2}cos(\frac{3x}{2})$
(b) See graph (red).