## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Amplitude, $A=|5|=5$ and period: $T=\dfrac{2\pi}{4}=\dfrac{\pi}{2}$
When the function has the form $y=A\sin{(\alpha x)}$, then $|A|$ denotes the amplitude and $T$ represents the period. The period $T$ can be computed as: $T=\dfrac{2\pi}{\omega}$. Here, we have: Amplitude, $A=|5|=5$ and period: $T=\dfrac{2\pi}{4}=\dfrac{\pi}{2}$