Answer
maximum, $f(2)=17$
Work Step by Step
Given $f(x)=-3x^2+12x+5$, we have $a=-3\lt0, b=12$, we can determine that it has a maximum at $x=-\frac{b}{2a}=-\frac{12}{2(-3)}=2$ and $f(2)=-3(2)^2+12(2)+5=17$
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