## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$2.83 \ square \ units$
According to Heron's formula, the area of a triangle with sides $a,b$ and $c$ is given by: $K=\sqrt{s(s-a)(s-b)(s-c)}$; where $s=\dfrac{a+b+c}{2}$ Therefore, $s=\dfrac{3+3+2}{2}=4$ In order to find the area of a triangle we will have to substitute the data into Heron's formula. $K=\sqrt{4(4-3)(4-3)(4-2)} \approx 2.83 \ square \ units$