Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 7 - Applications of Trigonometric Functions - Section 7.1 Right Triangle Trigonometry ; Applications - 7.1 Assess Your Understanding - Page 544: 85

Answer

$\frac{\sqrt 6-\sqrt 2}{4}$

Work Step by Step

Use the hint, $sin15^\circ=sin(45-30)^\circ=sin45^\circ cos30^\circ-cos45^\circ sin30^\circ=(\frac{\sqrt 2}{2})(\frac{\sqrt 3}{2})-(\frac{\sqrt 2}{2})(\frac{1}{2})=\frac{\sqrt 6-\sqrt 2}{4}$
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