Answer
amplitude$=5$, period$=\frac{\pi}{2}$, phase shift$=\frac{\pi}{4}$.
Work Step by Step
For $y=5cos(4x-\pi)=5cos[4(x-\frac{\pi}{4})]$, we can find the amplitude$=5$, period$=\frac{2\pi}{4}=\frac{\pi}{2}$, phase shift$=\frac{\pi}{4}$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.7 Product-to-Sum and Sum-to-Product Formulas - 6.7 Assess Your Understanding - Page 525: 58
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