Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.7 Product-to-Sum and Sum-to-Product Formulas - 6.7 Assess Your Understanding - Page 524: 4

Answer

$ \frac{\sqrt 6}{2}$

Work Step by Step

$sin75^\circ+ sin15^\circ=2sin(\frac{75^\circ+15^\circ}{2}) cos(\frac{75^\circ-15^\circ}{2})=2sin45^\circ cos30^\circ=2(\frac{\sqrt 2}{2})(\frac{\sqrt 3}{2})=\frac{\sqrt 6}{2}$
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