Answer
$\frac{9}{2}\pi\approx14.14\ cm^2$
Work Step by Step
Given $r=6\ cm, \theta=45^\circ=\frac{45}{180}\pi=\frac{1}{4}\pi$, we have the area $A=\frac{1}{2}r^2\theta=\frac{1}{2}6^2(\frac{1}{4}\pi)=\frac{9}{2}\pi\approx14.14\ cm^2$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.5 Sum and Difference Formulas - 6.5 Assess Your Understanding - Page 511: 114
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