Answer
See below.
Work Step by Step
Use the hint and the given figure, we have $\theta=\theta_2-\theta_1$ and
$tan\theta=tan(\theta_2-\theta_1)=\frac{tan\theta_2-tan\theta_1}{1+tan\theta_2 tan\theta_1}=\frac{m_2-m_1}{1+m_1m_2}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.5 Sum and Difference Formulas - 6.5 Assess Your Understanding - Page 510: 107
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