Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 496: 2

Answer

True

Work Step by Step

We know that $\sin$, $\csc$, and $\tan$ are odd trigonometric functions. This implies that $f(-\theta)=-f(\theta)$ So, $\sin(-\theta)=-\sin(\theta)$ We also know that $\cos$, $\sec$ are even trigonometric functions. This implies that $f(-\theta)=f(\theta)$ So, $\cos(-\theta)=\cos(\theta).$ Thus, $\sin(-\theta)+\cos(-\theta)=-\sin(\theta)+\cos(\theta) =\cos(\theta) -\sin (\theta) $ Therefore, the given statement is True.
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