Answer
$ (2x+1)^{-1/2}(x^2+3)^{-3/2}(-x^2-x+3)$
Work Step by Step
$(2x+1)^{-1/2}(x^2+3)^{-1/2}-(x^2+3)^{-3/2}x(2x+1)^{1/2}\\
=(2x+1)^{-1/2}(x^2+3)^{-3/2}(x^2+3-2x^2-x)
\\=(2x+1)^{-1/2}(x^2+3)^{-3/2}(-x^2-x+3)$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.1 The Inverse Sine, Cosine, and Tangent Functions - 6.1 Assess Your Understanding - Page 476: 84
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