Answer
$ -\frac{\sqrt 3}{2} $
Work Step by Step
$5sin^{-1}(x)-2\pi=2sin^{-1}(x)-3\pi \Longrightarrow 3sin^{-1}(x)=-\pi \Longrightarrow sin^{-1}(x)=-\frac{\pi}{3} \Longrightarrow x=sin(-\frac{\pi}{3})=-\frac{\sqrt 3}{2} $
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.1 The Inverse Sine, Cosine, and Tangent Functions - 6.1 Assess Your Understanding - Page 474: 68
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