Answer
$-\frac{1}{2},-1$.
Work Step by Step
Use a unit circle, we can find special trig function values and get $sin(-\frac{\pi}{6})=-sin(\frac{\pi}{6})=-\frac{1}{2}$ and $cos\pi=-1$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.1 The Inverse Sine, Cosine, and Tangent Functions - 6.1 Assess Your Understanding - Page 473: 6
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