Answer
$ \frac{-1\pm\sqrt {13}}{6}$
Work Step by Step
$3x^2+x-1=0$,
$x=\frac{-1\pm\sqrt {1+4(3)}}{2(3)}
=\frac{-1\pm\sqrt {13}}{6}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Cumulative Review - Page 529: 1
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