Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.5 Graphs of the Tangent, Cotangent, Cosecant, and Secant Functions - 5.5 Assess Your Understanding - Page 443: 56

Answer

$ -1, 3$.

Work Step by Step

$9^{x-1}=3^{x^2-5} \Longrightarrow (x-1)ln9=(x^2-5)ln3 \Longrightarrow x^2-5=2x-2 \Longrightarrow x^2-2x-3=0 \Longrightarrow (x+1)(x-3)=0 \Longrightarrow x=-1, 3$.
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