Answer
$(-\infty,\infty)$.
Work Step by Step
$x^2-5=(x+3)(x-3)+4 \Longrightarrow x^2-5=x^2-9+4 \Longrightarrow -5=-5 $, thus the solution is $x\in(-\infty,\infty)$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Section 5.3 Properties of the Trigonometric Functions - 5.3 Assess Your Understanding - Page 420: 137
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