Answer
H.A. $y=3$, V.A. $x=7$.
Work Step by Step
$R(x)=\frac{3x^2-12}{x^2-5x-14}=\frac{3(x^2-4)}{(x+2)(x-7)}=\frac{3(x+2)(x-2)}{(x+2)(x-7)}=\frac{3x-6}{x-7}$, thus we have H.A. $y=3$, V.A. $x=7$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Section 5.1 Angles and Their Measures - 5.1 Assess Your Understanding - Page 389: 137
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
