Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Cumulative Review - Page 461: 13

Answer

$y=3cos(\frac{\pi}{6}x)$

Work Step by Step

1. The given curve resembles a cosine function with a general form $y=A\ cos(kx)$ 2. We can find the amplitude$=3$, period$=6-(-6)=12$. 3. We have $A=3$, $\frac{2\pi}{k}=12$, thus $k=\frac{\pi}{6}$. 4. Thus we have $y=3cos(\frac{\pi}{6}x)$
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