Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Chapter Review - Review Exercises - Page 459: 46

Answer

$sin(t)= \frac{5\sqrt {29}}{29}$, $cos(t)= -\frac{2\sqrt {29}}{29}$, $tan(t)= -\frac{5}{2}$.

Work Step by Step

Given $x=-2, y=5$, we have $r=\sqrt {(-2)^2+5^2}=\sqrt {29}$ and: $sin(t)=\frac{y}{r}=\frac{5\sqrt {29}}{29}$, $cos(t)=\frac{x}{r}=-\frac{2\sqrt {29}}{29}$, $tan(t)=\frac{y}{x}=-\frac{5}{2}$.
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