Answer
$ \$ 697.09$
Work Step by Step
Recall:
$A = P \left(1+\dfrac{r}{n} \right)^{n t}$
where
$P:$ The principal amount
$r:$ Annual interest rate
$n:$ Number of compoundings per year
$t:$ Number of years
$A:$ Amount after $t$ years
The given problem has:
$P= \$ 600, r=0.05, t = 3$
$\text{Compounded daily} \to n = 365$
Thus, using these values and the given formula above gives:
$A = 600 \left(1+\dfrac{0.05}{365} \right)^{365 \times 3}$
$A \approx \$ 697.09$
