Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.3 Exponential Functions - 4.3 Assess Your Understanding - Page 310: 122

Answer

$f(-x)=a^{-x}=\dfrac{1}{a^x}=\dfrac{1}{f(x)}$

Work Step by Step

Given , $f(x)=a^{x}$...........$(1)$ Then, $f(-x)= a^{-x}$...........[from (1)] $f(-x)= \frac{1}{a^{x}}$........[by laws of exponents] $f(-x)= \frac{1}{f(x)}$ ..........[by using (1)] Hence Proved.
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